Respuesta :

We have:

Time (t) = 9.0 seconds
Acceleration (a) = -9.8 m/s²
Final Velocity (v) = 0 m/s ⇒ It's zero as the object's speed stops when it hits the ground

Using one of the constant acceleration equation
s = vt - ¹/₂at²
s = (0×9) - (0.5 × -9.8 × 9)
s = 0 + 44.1
s = 44.1 metres 


Answer:

The distance that it fell is [tex]396.9\rm metre[/tex]

Explanation:

Given information:

Height of the building = [tex]h \rm metre[/tex]

Time=[tex]0.9\rm sec[/tex]

acceleration due to gravity [tex]a=g=9.8\rm m/s^2[/tex]

Taken as positive  because the speed is increasing downward

By using, equation of motion,

[tex]h=ut+\frac{1}{2}at^2=0\times t+\frac{1}{2}gt^2[/tex]

[tex]h=\frac{1}{2}9.8\rm m/s^2\times (9s)^2=396.9metre[/tex]

The distance that it fell is [tex]396.9\rm metre[/tex]

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