For this case we must find the value of "x" of the following expression:
[tex]3x-8 = \frac {8x + 4} {2}[/tex]
Multiplying by 2 on both sides of the equation:
[tex]2 (3x-8) = 8x + 4\\6x-16 = 8x + 4[/tex]
Subtracting 8x from both sides of the equation:
[tex]6x-8x-16 = 4\\-2x-16 = 4[/tex]
Adding 16 to both sides:
[tex]-2x = 4 + 16\\-2x = 20[/tex]
Dividing between -2 on both sides:
[tex]x = \frac {20} {- 2}\\x = -10[/tex]
Answer:
[tex]x = -10[/tex]
