Answer: There are [tex]\dfrac{4}{3}[/tex] numbers of [tex]\dfrac{3}{4}[/tex] in 1.
Step-by-step explanation: We are given to find the number of [tex]\drac{3}{4}[/tex] in 1.
Let n be the number of [tex]\drac{3}{4}[/tex] that are present in 1.
So, we must have
[tex]n\times\dfrac{3}{4}=1\\\\\\\Rightarrow n=\dfrac{1}{\frac{3}{4}}\\\\\\\Rightarrow n=1\times\dfrac{4}{3}\\\\\\\Rightarrow n=\dfrac{4}{3}.[/tex]
Thus, there are [tex]\dfrac{4}{3}[/tex] numbers of [tex]\dfrac{3}{4}[/tex] in 1.