Calculate the circumference of the circular path of the wheel by the equation,
C = 2πr
where C is the circumference,
r is the radius
Substituting the known values,
C = 2(π)(0.487 m) = 3.06 m
Then, period of the motion will be determined by dividing the number of rotations done,
T = (3.06 m) / (5.75 /s) = 0.53 s
ANSWER: 0.53 s