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a pet store has 30 animals. some are cats the rest are dogs. the cats cost $50 each. the dogs cost $100 each. if the total for all 30 animals is $1900, how many cats are there?

Respuesta :

Kimberlync
Dogs= X
Cats= Y

X + Y = 30

100x + 50y= 1900

Easiest way is to solve by substitution.

[Looking for Y]

x+y=30

[subtract Y]

X= 30- Y

—————

Next, plug that into the next equation.

100 (30-y) + 50y= 1900

[Distribute]

300- 100y + 50y= 1900

[Combine Like Terms]

300- 50y= 1900

[subtract 300]

-50y= 1600

[divide by -50]

Y= ANSWER

This is Systems of Equations.

Answer:

There are 22 cats and 8 dogs.

Step-by-step explanation:

Let the cats be represented by = c

Let the dogs be represented by = d

Given, that the pet store has 30 pets.

First equation forms :

[tex]c+d=30[/tex]            ........(1)

Also given, the cats cost $50 each and dogs cost $100 each and the total for all is $1900. Now second equation forms:

[tex]50c+100d=1900[/tex]     .........(2)

From equation (1) we get [tex]c=30-d[/tex]

Putting this value of c in equation 2:

[tex]50(30-d)+100d=1900[/tex]

[tex]1500-50d+100d=1900[/tex]

=> [tex]50d=400[/tex]

=> [tex]d=8[/tex]

Now,[tex]c+d=30[/tex]

So, [tex]c=30-8[/tex]

[tex]c=22[/tex]

Hence, there are 22 cats and 8 dogs.

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