Answer:
[tex](y-5)^2=-8x[/tex]
Step-by-step explanation:
vertex is (0, 5) and whose directrix is x = 2
Vertex (0,5), x=0 and y=5
The distance between x=0 and x=2 is 2 units
The distance between vertex and directrix is P
p= 2
General equation of horizontal parabola is
[tex](y-k)^2=-4p(x-h)[/tex]
h=0, y= 5, p=2
[tex](y-5)^2=-4(2)(x-0)[/tex]
[tex](y-5)^2=-8x[/tex]
