Respuesta :
For the first question we use point-slope form of an equation
y-[tex] y_{1} [/tex]=m(x-[tex] x_{1} [/tex])
y=m(x-[tex] x_{1} [/tex])+[tex] y_{1} [/tex]
then we plug in the known values
y=m(x-4)+7
we leave the slope as variable m since it is undefined
For Question 2
A line that is parallel to the x-axis is a horizontal line and since the slope of a line is defined as the Δy/Δx (change in y/change in x) and the change in y is 0 at any 2 points observed on the line the slope is 0. (0/any number is 0)
For Question 3
Following the same relationship as question 2 we can solve for the slope.
Δy/Δx
[tex] y_{1} [/tex]-[tex]y _{2} [/tex]/[tex] x_{1} [/tex]-[tex] x_{2} [/tex]
now we plug in the known values from the two points given
(5-7)/(-3-1)
-2/-4
m=1/2 or 0.5
and For the Final Question
a translation left or right is done by affecting the x variable if you add 2 to x then the x value will have to be 2 less to get the same result...in other words when x is 1 the value of y is also 1...but if I wanted the whole equation translated left 2 unites then I would want the same y-value at an x-value 2 smaller... in other words, in our example x will be -1 when y is 1. For this value found on the graph to match the equation our x value must have 2 added to it in the equation....therefore the equation that translates y=|x| two units left is...
y=|x+2|
y-[tex] y_{1} [/tex]=m(x-[tex] x_{1} [/tex])
y=m(x-[tex] x_{1} [/tex])+[tex] y_{1} [/tex]
then we plug in the known values
y=m(x-4)+7
we leave the slope as variable m since it is undefined
For Question 2
A line that is parallel to the x-axis is a horizontal line and since the slope of a line is defined as the Δy/Δx (change in y/change in x) and the change in y is 0 at any 2 points observed on the line the slope is 0. (0/any number is 0)
For Question 3
Following the same relationship as question 2 we can solve for the slope.
Δy/Δx
[tex] y_{1} [/tex]-[tex]y _{2} [/tex]/[tex] x_{1} [/tex]-[tex] x_{2} [/tex]
now we plug in the known values from the two points given
(5-7)/(-3-1)
-2/-4
m=1/2 or 0.5
and For the Final Question
a translation left or right is done by affecting the x variable if you add 2 to x then the x value will have to be 2 less to get the same result...in other words when x is 1 the value of y is also 1...but if I wanted the whole equation translated left 2 unites then I would want the same y-value at an x-value 2 smaller... in other words, in our example x will be -1 when y is 1. For this value found on the graph to match the equation our x value must have 2 added to it in the equation....therefore the equation that translates y=|x| two units left is...
y=|x+2|
1.
Answer:
[tex]y = m(x - 4) + 7[/tex]
Explanation:
as we know that equation of straight line passing through a fixed point and having undefined slope is given as
[tex]y - y_1 = m(x - x_1)[/tex]
here we have
[tex](x_1, y_1) = (4, 7)[/tex]
so we will have
[tex]y - 7 = m(x - 4)[/tex]
[tex]y = m(x - 4) + 7[/tex]
2.
Answer:
slope = ZERO
Explanation:
Slope of the straight line is defined as the tangent of the angle made by the line with respect to x axis
here we need to find the slope of a straight line parallel to x axis so the angle is ZERO degree
hence the slope will be given as
[tex]m = tan 0 [/tex]
[tex]m = 0[/tex]
3.
Answer:
[tex]m = 0.5[/tex]
Explanation:
Slope of a straight line passing through two different points is given as
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
here we will have
[tex]m = \frac{7 - 5}{1 + 3}[/tex]
[tex]m = \frac{2}{4}[/tex]
[tex]m = 0.5[/tex]
4.
Answer:
[tex]y = |x - x'|[/tex]
here x' = any positive number
Explanation:
If we translate the graph 2 units left of the given position so we can say that we have shifted the graph above from its given position.
So we will have
[tex]y = |x - x'|[/tex]
here x' = any positive number