n △JKL, KN=21 m.
What is the length of KX?

Answer:
[tex]KX = 14m[/tex]
Step-by-step explanation:
To solve this problem, we need to use the theorem about the intersection of all three medians, which states
"The medians of a triangle concurrent at a point that is two-thirds from each vertex to the mid point at the opposite side".
If we apply this theorem, we have
[tex]KX = \frac{2}{3}KN[/tex]
So, if [tex]KN = 21 m[/tex]
Then,
[tex]KX = \frac{2}{3}21m=14m[/tex]
Therefore,
[tex]KX = 14m[/tex]