Answer:
Option D. is the answer.
Step-by-step explanation:
we have to simplify the cube root of [tex]\frac{\sqrt[3]{7}}{\sqrt[5]{7} }[/tex]
= [tex]\frac{7^{\frac{1}{3}}}{7^{\frac{1}{5} } }[/tex]
= [tex]7^{\frac{1}{3}-\frac{1}{5}}[/tex]
= [tex]7^{(\frac{5-3}{15})}[/tex]
= [tex]7^{\frac{2}{15}}[/tex]
Therefore, Option D. 7 to the power of 2 over 15 is the answer.
