Ediebug
contestada

Factoring Trinomials
25a^2+20ab+4b^2
If you don't understand I can send you a picture of the problem. :)

Respuesta :

25 a² + 20 ab +  4 b²

for formula [tex]a^x+bx^ky^k+cy ^{2k } [/tex] find  u,v such that: u.v = a

and u+v = b  then  group according to [tex](ax ^{2k} +ux^ky^k)+(vx^ky^k+cy ^{2k} )[/tex]

= [tex](25a^2+10ab)+(10ab+4b^2)[/tex]

factor out 5a from : [tex]25a^2+10ab : 5a(2b+5a)[/tex]

factor out 2b from : [tex]10ab+4b^2: 2b(2b+5a)[/tex]

= [tex]5a(2b+5a) + 2b(2b+5a)[/tex]

factor out : [tex](5a+2b)[/tex]

= [tex](5a+2b)(5a+2b)[/tex]

Refine:

[tex](2b+5a)^2[/tex]

hope this helps!.