flirtmcfelt
flirtmcfelt
16-08-2014
Mathematics
contestada
12-[20-2(6^2/3•2^2)]
Respuesta :
Аноним
Аноним
16-08-2014
12-[20-2(6²/3*2²)]
=12-[20-2(36/3*4)]
=12-[20-2(12*4)]
=12-[20-2(48)]
=12-[20-96]
=12-(-76)
=12+76
=88
Answer Link
kate200468
kate200468
16-08-2014
[tex]12-\bigg{[}20-2\cdot \bigg{(} \frac{\big{6^2}}{\big{3}} \cdot2^2\bigg{)}\bigg{]}=12-\bigg{[}20-2\cdot \bigg{(} \frac{\big{36}}{\big{3}} \cdot4\bigg{)}\bigg{]}=\\\\=12-(20-2\cdot 12 \cdot4)=12-(20-96)=12-(-76)=12+76=88[/tex]
Answer Link
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