Respuesta :
First, you change 6 3/8 and 3 1/4 to a common denminator. 8
6 3/8= 6 3/8
3 1/4= 3 2/8 (x2)
Then add those.
6 3/8+ 3 2/8 = 9 5/8
Then subtract 22 1/2 and 9 5/8. (Common denominator)
22 1/2= 22 4/8 (x4)
9 5/8= 9 5/8
the 3rd bag is 12 7/8 lbs.
You can also add each bag (lbs) to see if it gets to 22 1/2
Hope this helps!
6 3/8= 6 3/8
3 1/4= 3 2/8 (x2)
Then add those.
6 3/8+ 3 2/8 = 9 5/8
Then subtract 22 1/2 and 9 5/8. (Common denominator)
22 1/2= 22 4/8 (x4)
9 5/8= 9 5/8
the 3rd bag is 12 7/8 lbs.
You can also add each bag (lbs) to see if it gets to 22 1/2
Hope this helps!
3 bags total 22 and 1/2
bag1+bag2+bag3=22 and 1/2
two of the bags weight 6 and 3/8 and 3 and 1/4 so just assign them random bags
bag1=6 and 3/8
bag2=3 and 1/4
subsitute
6 and 3/8+3 and 1/4+bag3=22 and 1/2
we have to add them by making the bottom number same
6 and 3/8+3 and 1/4
common one is 8
6 and 3/8+3 and 2/8
6+3/8+3+2/8
9+5/8
9 and 5/8+bbag3=22 and 1/2
subtract 9 and 5/8 from both sides
bag3=22 and 1/2-9 and 5/8
bag3=22+1/2-9-5/8
bag3=22+4/8-9-5/8
bag3=21+8/8+4/8-9-5/8
bag3=21+12/8-9-5/8
bag3=21-9+12/8-5/8
bag3=12+7/8
bag3=12 and 7/8
answe ris 12 and 7/8 pounds
bag1+bag2+bag3=22 and 1/2
two of the bags weight 6 and 3/8 and 3 and 1/4 so just assign them random bags
bag1=6 and 3/8
bag2=3 and 1/4
subsitute
6 and 3/8+3 and 1/4+bag3=22 and 1/2
we have to add them by making the bottom number same
6 and 3/8+3 and 1/4
common one is 8
6 and 3/8+3 and 2/8
6+3/8+3+2/8
9+5/8
9 and 5/8+bbag3=22 and 1/2
subtract 9 and 5/8 from both sides
bag3=22 and 1/2-9 and 5/8
bag3=22+1/2-9-5/8
bag3=22+4/8-9-5/8
bag3=21+8/8+4/8-9-5/8
bag3=21+12/8-9-5/8
bag3=21-9+12/8-5/8
bag3=12+7/8
bag3=12 and 7/8
answe ris 12 and 7/8 pounds