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It is desired to lay off certain horizontal distances for building layouts. The length of the tapes are not 100.00 ft. Determine the field dimensions that should be used with the incorrect tape the lengths so that the correct dimensions are obtained. Desired dimension: 725.00 by 180.00 ft Incorrect tape length: 100.06 ft

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adelekeademolu

Answer:

725.44 by 180.11

Explanation:

If a 100-ft tape was used, the number of such tapes in 725 ft would be [tex]\dfrac{725}{100}=7.25[/tex]

And in 180 ft would be [tex]\dfrac{180}{100}=1.8[/tex]

The same number of tapes would be used for the incorrect tape to give the false dimension. This would be

[tex]100.06\times7.25[/tex] by [tex]100.06\times1.8[/tex] =

[tex]725.44[/tex] by [tex]180.11[/tex]

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